1-(2/2t-1)=(8/(2t-1)^2)

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Solution for 1-(2/2t-1)=(8/(2t-1)^2) equation: 



1-(2/2t-1)=(8/(2t-1)^2)

We move all terms to the left:

1-(2/2t-1)-((8/(2t-1)^2))=0



Domain of the equation: 2t-1)!=0

t∈R





Domain of the equation: (2t-1)^2))!=0

t∈R



We get rid of parentheses

-2/2t-((8/(2t-1)^2))+1+1=0

We calculate fractions


(-4t)/2t^2+(-((8*2t)/2t^2+1+1=0

We add all the numbers together, and all the variables

(-4t)/2t^2+(-((+8*2t)/2t^2+1+1=0

We calculate fractions

We do not support etpression: t^4

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